A particle executes SHM with amplitude 0.2m and time period 24 sec. The time required by it to move from mean position to a point 0.1 m from the mean position is:
A particle executes simple harmonic motion about the point X =0 . At time t =0 it has displacement cm and zero velocity. If the frequency of motion is 0.25sec−2, find (a) the time period, (b) angular frequency, (c) the amplitude, (d) maximum speed, (e) the displacement at t =3 sec and (f) the velocity at t =3 sec.