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Question

1417×1417 can be represented as


A

(14)1/7 + 1/7

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B

(14 x 14)1/7

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C

(142)1/7

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D

All of the above

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Solution

The correct options are
A

(14)1/7 + 1/7


B

(14 x 14)1/7


C

(142)1/7


For any positive real 'a' and integers 'm' and 'n' we define am×an=am+n and (am)n=amn
Here, a=14,m=n=17. So,
1417+17=1427=(142)17


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