The correct option is C 2 We have, #160; cos^ 1 (4149) = #160;cos^ 1 (1 2 ( #160;27)^2 ) Let sin θ = 27 Hence, #160; cos^ 1 (4149) ...

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Higher Order Derivatives

cos-141/49/si...

Question

$\frac{c o s^{- 1} (41 / 49)}{s i n^{- 1} (2 / 7)} =$

4

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Solution

The correct option is C $2$
We have,
$c o s^{- 1} (\frac{41}{49}) = c o s^{- 1} (1 - 2 {(\frac{2}{7})}^{2})$
Let $s i n θ = \frac{2}{7}$
Hence,
$c o s^{- 1} (\frac{41}{49}) = c o s^{- 1} (c o s 2 θ) = 2 θ$
$∴ {cos}^{- 1} {\frac{41}{49}} = 2 {sin}^{- 1} {\frac{2}{7}}$
So, $\frac{{cos}^{- 1} (\frac{41}{49})}{{sin}^{- 1} \frac{2}{7}} = 2$
Hence, option C is correct.

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