14 g of nitrogen contains 3-01 - 1023 nitrogen molecules-

The correct option is A True1 mole nitrogen contains 6.02×10^23 nitrogen molecules.Thus 14 gram nitrogen will contain 14/28.Na=0.5Na=3.01×10^23 nit ...

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Standard XII

Chemistry

Gay Lussac's Law, Avagadro's Law

14 g of nitro...

Question

14 g of nitrogen contains $3.01 \times 10^{23}$ nitrogen molecules.

True

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False

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Solution

The correct option is A True
1 mole nitrogen contains $6.02 \times 10^{23}$ nitrogen molecules.
Thus 14 gram nitrogen will contain $14 / 28. N a = 0.5 N a = 3.01 \times 10^{23}$ nitrogen molecules. ( Molecular weight of nitrogen is 28)

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14 g of nitrogen contains 3.01×1023 nitrogen molecules.

The correct option is A True1 mole nitrogen contains 6.02×1023 nitrogen molecules.Thus 14 gram nitrogen will contain 14/28.Na=0.5Na=3.01×1023 nitrogen molecules. ( Molecular weight of nitrogen is 28)

14 g of nitrogen contains $3.01 \times 10^{23}$ nitrogen molecules.

The correct option is A True
1 mole nitrogen contains $6.02 \times 10^{23}$ nitrogen molecules.
Thus 14 gram nitrogen will contain $14 / 28. N a = 0.5 N a = 3.01 \times 10^{23}$ nitrogen molecules. ( Molecular weight of nitrogen is 28)