$14$ tins contains $210$ liters of oil. How much oil is contained in $1$ tin?

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Solution

By unitary method, we have:
Cost of $14$ tins $= 210$ liters
Cost of $1$ tin $= (\frac{210}{14}) = 15$ liters $[L e s s t i n s, l e s s l i t e r s]$
Hence, the oil in $1$ tin is $15$ liters

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