Question

A tin contains $2\frac{5}{6}l$ of oil, $1\frac{3}{8}l$ of oil gets leaked. How much oil is left in the tin?

Answer 1

Oil left = initial constant - oil leaked

$=2\frac{5}{6}-1\frac{3}{8}$

$=\frac{6\times 2+5}{6}-\frac{8\times 1+3}{8}$

$=\frac{17}{6}-\frac{11}{8}=\frac{68-33}{24}$

$=\frac{35}{24}L$