$15$ joule of work has to be done to take a charge of $0.01 C$ from $A$ to $B$ . The potential difference $(V_{B} - V_{A})$ is

1500

volt

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- 1500

volt

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0.15

volt

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None of these

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Solution

The correct option is A $1500$ volt
Work done in carrying a charge is equal to

$W = q d V$

So potential difference between the two points is equal to

$V_{B} - V_{A} = (\frac{15}{0.01}) V$

$= 1500 V$

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5 μ C

(V_{B} - V_{A})

100

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- 10

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