MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Divisibility by 5

" 18! + 1 is ...

Question

" 18! + 1 is divisible by 19 and 23 " prove it .

Open in App

Solution

Suggest Corrections

thumbs-up

0

Similar questions

The remainder obtained when $23^{21} - 19^{21}$ is divisible by 21 is

5^{17} + 5^{18} + 5^{19} + 5^{20}

is divisible by

Q. Using binomial theorem, prove that

2^{3 n} - 7 n - 1

is divisible by 49, where

n \in N

Q. Make the correct alternative in the following question:

For all n \in N, 3 \times 5^{2 n + 1} + 2^{3 n + 1} is divisible by

(a) 19 (b) 17 (c) 23 (d) 25

Q. 23 is a composite number because it is divisible by 1.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Why Divisibility Rules?

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Divisibility by 5

Standard VIII Mathematics

Join BYJU'S Learning Program

CrossIcon