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18.A boy thro...

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18.A boy throws balls into air at regular interval of 2second.The next ball is thrown when the velocity of the first ball is zero.How high do the ball rise above his hand?takeg=9.8m/s^2?

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Q. A boy throws balls into air at regular interval of

2

second. The next ball is thrown when the velocity of first ball is zero. How high do the ball rise above his hand? [Take

g = 9.8 m / s^{2}]

.

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[T a k e g = 10 m / s^{2}]

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