18. Energy required for ionization of 0.02 gram atom of magnesium is x kJ. The amount of energy required to ionise 1 atoom of magnesium is 1) x kJ 2) x / (0.02 * NA) J 3) (x1000 ) / (0.02 NA) J 4) x NA J

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x

x \times 10^{6} J

x

Na = 5.1 eV/atom

{m o l}^{- 1}

{m o l e c u l e}^{- 1}

x \times 10^{- 1}

H

x k J

n = 2

n = 3

6.64 e V

13.36 e V

M g^{2 +}

12 m g

[G i v e n : 1 e V = 96.5 k J / m o l]

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18. Energy required for ionization of 0.02 gram atom of magnesium is x kJ. The amount of energy required to ionise 1 atoom of magnesium is 1) x kJ 2) x / (0.02 * NA) J 3) (x*1000 ) / (0.02 * NA) J 4) x NA J