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Elevation in Boiling Point

18 g of gluco...

Question

$18 g$ of glucose, $C_{6} H_{12} O_{6}$ is dissolved in $1 k g$ of water in a saucepan. At what temperature will the water boil
under atmospheric pressure? $K_{b}$ for water is $0.52 K k g m o l^{- 1}$

373.052 K

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373.52 K

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373.25 K

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373.152 K

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Solution

The correct option is A $373.052 K$
Boiling point elevation of a solution is given by,
$△ T_{b} = K_{b} \times m$
where,
$△ T_{b}$ is the elevation in boiling point.
$K_{b}$ is molal elevation constant.
m is molality of solution.
$Molality = \frac{△ T_{b}}{K_{b}} = \frac{△ T_{b}}{0.52}$
Given,
Mass of the glucose = $18 g$
No. of moles of glucose $= \frac{18}{180}$
$Molality (m) = \frac{n_{solute} \times 1000}{W_{solvent} in gram}$
$∴$
$Molality = \frac{18}{180} \times \frac{1000}{1000} m o l / k g$
$∴$
$△ T_{b} = 0.52 \times \frac{18 \times 1000}{180 \times 1000}$
$Boiling point of pure water, T = 373 K$
$△ T_{b} = 0.052 T - 373 K = 0.052$
Thus, the temperature at which the given sugar solution boil is at $373.052 K$

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Similar questions

Q. 18 g of glucose,

C_{6} H_{12} O_{6}

, is dissolved in 1 kg of water in a saucepan. At what temperature will the water boil (1.013 bar pressure)?

K_{b}

for water is 0.52 K kg

m o l^{- 1}

18 g

of glucose,

C_{6} H_{12} O_{6}

(Molar mass = 180 g

m o l^{- 1})

is dissolved in

1 k g

of water in a saucepan. At what temperature will this solution boil?
(

K_{b}

for water =

0.52 K k g m o l^{- 1}

, boiling points of pure water =

373.15 K

)

18 g

of glucose

(C_{6} H_{12} O_{6})

is dissolved in

1 k g

of water in a saucepan. At what temperature will the water boil at

1.013 b a r

[

K_{b}

for water is

0.52 K k g m o l^{- 1}

]

18g of glucose $(C_{6} H_{12} O_{6})$ is dissolved in 1 kg of water in a saucepan. At what temperature will the water boil (at 1 atm)? $K_{b}$ for water is $0.52 K k g m o l^{- 1}$ .

if ebullioscopic constant of water is 0.52 K kg/mol and 1 kg of water with 18 g of glucose dissolved in it will boil at

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Elevation in Boiling Point

Standard XII Chemistry

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18 g of glucose, C6H12O6 is dissolved in 1 kg of water in a saucepan. At what temperature will the water boil under atmospheric pressure? Kb for water is 0.52 K kg mol−1

$18 g$ of glucose, $C_{6} H_{12} O_{6}$ is dissolved in $1 k g$ of water in a saucepan. At what temperature will the water boil
under atmospheric pressure? $K_{b}$ for water is $0.52 K k g m o l^{- 1}$