Boiling point elevation of a solution is given by,
△Tb=Kb×m
where,
△Tb is the elevation in boiling point.
Kb is molal elevation constant.
m is molality of solution.
Molality =△TbKb=△Tb0.52
Given,
Mass of the glucose = 18 g
No. of moles of glucose =18180
Molality (m)=nsolute×1000Wsolventin gram
∴
Molality =18180×10001000 mol/kg
∴
△Tb=0.52×18×1000180×1000
Boiling point of pure water, T=373 K
△Tb=0.052T−373 K=0.052
Thus, the temperature at which the given sugar solution boil is at 373.052 K