Question

18 g of ice at $0^{o}C$ is mixed with 1g of water at ${100}^{o}C$. The resulting temperature will be :

• A. $\infty$
• B. ${10}^{o}C$
• C. $0^{o}C$
• D. $5^{o}C$

Answer 1

Answer: (C)

$0^{o}C$

Let the final temperature be $T$ and final state be liquid.

$18\left(80\right)+18\left(1\right)(T-0)=1\left(1\right)(100-T)$

Since from this equation, temperature comes out to be negative which is not possible since final temperature cannot fall. Hence, our assumption that complete ice will melt is incorrect and hence the mixture will exist as ice water equilibrium at $0^{0}C$.