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Question

1g mixture of CaCO3 and NaCl reacts completely with 100 ml of N/10 HCl. The % of CaCO3 in the mixture is

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Solution

1 g mix contains x g of CaCO3​ & 1−x g NaCl
CaCO​3+2HCl→H2​CO3​+CaCl2​
HCl=101​×0.1L
=0.01 moles of HCl =2×moles of CaCO3​
So moles of CaCO3​
=20.01​
=0.005
mass of CaCO3​=5×10−3×100
=0.5g

% of CaCO3​=10.5​×100
=50 %


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