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Question

According to the CaCO3+HClCaCl2+CO2+H2O. What mass of CaCO3 is required to react completely with 25ml. of 0.75M HCl?

A
0.9945 g
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B
0.6645 g
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C
0.9375 g
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D
0.8555 g
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Solution

The correct option is A 0.9375 g
Using morality, Number of moles are calculated for 1000ml or 1L of the solution.
1000ml contains 0.75MHCl
HCl=0.75 mole.
Therefore, 25ml of 0.75M HCl will contains HCl=0.75×251000=0.01875mole
2 moles of HCl reacts with =1mole of CaCO3
Therefore,
0.01875 mole of HCl will react with =1×0.018752
=0.009375mole
Molar mass of CaCO3=100g
Hence, the mass of 0.009375 of CaCO3=no.ofmoles×molarmass=0.9375g

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