Question

1g of the Ag salt of an organic dibasic acid yields, on strong heating, 0.5934 g of silver. If the weight $\%$ of carbon in it is 8 times the weight $\%$ of hydrogen and half the weight percentage of oxygen, determine the molecular formula of the acid [Atomic wt of Ag = 108]

• A. $C_4{H}_6{O}_4$
• B. $C_4{H}_6{O}_6$
• C. $C_2{H}_6{O}_2$
• D. $C_5{H}_{10}{O}_5$

Answer 1

The correct option is B $C_4{H}_6{O}_6$

$W_{salt}=1g$ Let Wt $\%$ of H $=x$
$W_{Ag}=0.5934g$ Let Wt of C $=8x$
Let Wt of O $=16x$
Since its dibasic acid
$\therefore$ mole of salt = 2 moles of Ag
$\therefore$ moles of Ag $=\frac{0.5934}{108}$
$\therefore$ moles of salt/Acid $=\frac{0.5934}{108}\times \frac{1}{2}$
Given amount of salt = 1g
$\therefore$ Molecular amount of salt $=\frac{1}{0.5934}\times 108\times 2$
$=364g/mol$
now $x+8x+16x=364$
$x=14.5g$
$\therefore$ moles of $H_{2}O=14.5$
Since 4+0 are equal hence option b.