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Temperature

1kg of water ...

Question

1kg of water and 1kg of steel are heated through 1K. The change in their internal energies are :
(Specific heat of steel $=$ 460 J/kg/K ; Specific heat of water $=$ 4200J/kg/K)

460 J, 4200 J

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4200 J, 460 J

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1000 J, 4200 J

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460 J, 1000 J

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Solution

The correct option is C 4200 J, 460 J
Change in internal energy of the system is given by $U_{f} - U_{i} = m C (T_{f} - T_{i})$

For water :
$Δ U = 1 \times 4200 \times 1$
$= 4200 J$

For steel :
$Δ U = 1 \times 460 \times 1$
$= 460 J$

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k g^{- 1} K^{- 1}

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- 10^{o} C

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7, 77, 000 J

= 2100 J k g^{- 1} K^{- 1}

= 4200 J k g^{- 1} K^{- 1}

The specific heat capacity of water is :

(a) 4200 J k $g^{- 1} K^{- 1}$ (b) 420 J k $g^{- 1} K^{- 1}$

10

^{o}

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50

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^{- 1}

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1 kg

- 10^{\circ} C

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= 2100 J {k g}^{- 1} K^{- 1}

= 3.36 \times 10^{5} J {k g}^{- 1}

= 4200 J {k g}^{- 1} K^{- 1}

= 2.25 \times 10^{6} J {k g}^{- 1}

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