$- 2 - 3 =$ ___

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Solution

If you are already standing on a ( $- 2$ ) on a number line and you are told to move $3$ places to your left, you would be at ( $- 5$ ).

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$- 2 - 3 = ?$

2^{3} \times 3^{3} \times 7^{2}

b = 2^{2} \times 3^{2} \times 5^{3},

3 y \sqrt{2} = 144 \sqrt{3} = 1.732 f i n d t h e v a l u e o f \frac{4}{3 \sqrt{3} - 2 \sqrt{2}} + \frac{3}{3 \sqrt{3} + 2 \sqrt{2}}

\frac{3 \sqrt{2} - 2 \sqrt{3}}{3 \sqrt{2} + 2 \sqrt{3}} + \frac{\sqrt{8}}{\sqrt{3} - \sqrt{2}}

\frac{1^{3} + 2^{3} + 3^{3} + 4^{3} + . . . . . . . {.12}^{3}}{1^{2} + 2^{2} + 3^{2} + 4^{2} + . . . . . {.12}^{2}} =

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