The correct option is A 8^5We know that a^m × b^m = (a × b)^m where a and b are nbsp;non zero integers. ⇒(2)^5 ×(4)^5 =(2× 4)^5= (8)^5 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VII

Mathematics

a^m x b^m = (ab)^m

25× 45=

Question

$2^{5} \times 4^{5}$ =

8^{5}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

8^{- 5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

24^{5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8^{5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $8^{5}$
We know that $a^{m} \times b^{m} = {(a \times b)}^{m}$
where a and b are non-zero integers.

$\Rightarrow {(2)}^{5} \times {(4)}^{5} = (2 \times 4)^{5} = {(8)}^{5}$

Suggest Corrections

Similar questions

Q. If

\frac{4^{5} + 4^{5} + 4^{5} + 4^{5}}{2^{5} + 2^{5}} \times \frac{6^{5} + 6^{5} + 6^{5} + 6^{5} + 6^{5} + 6^{5}}{3^{5} + 3^{5} + 3^{5}} = 8^{n}

, then n is:

45 - [45 - {25 - (8 - 4)}]

Let N = $\frac{4^{5} + 4^{5} + 4^{5} + 4^{5}}{3^{5} + 3^{5} + 3^{5}} \cdot \frac{6^{5} + 6^{5} + 6^{5} + 6^{5} + 6^{5} + 6^{5}}{2^{5} + 2^{5}}$ then the value of ${log}_{2} N$ =

Q. Let

N = \frac{4^{5} + 4^{5} + 4^{5} + 4^{5}}{3^{5} + 3^{5} + 3^{5}} . \frac{6^{5} + 6^{5} + 6^{5} + 6^{5} + 6^{5} + 6^{5}}{2^{5} + 2^{5}}

, then the value of

{log}_{2} N =

Q. 75 - (45 + 25) = ?

Join BYJU'S Learning Program

25×45 =

The correct option is A 85We know that am×bm=(a×b)m where a and b are non-zero integers. ⇒(2)5×(4)5=(2×4)5=(8)5

$2^{5} \times 4^{5}$ =

The correct option is A $8^{5}$
We know that $a^{m} \times b^{m} = {(a \times b)}^{m}$
where a and b are non-zero integers.

$\Rightarrow {(2)}^{5} \times {(4)}^{5} = (2 \times 4)^{5} = {(8)}^{5}$