2-56 g of sulphur in 100 g of CS2 has depression in freezing point of 0-010-C- Atomicity of sulphur is CS2 is-Given- Kf - 0-1- molal-1

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Byju's Answer

Standard XII

Chemistry

Depression in Freezing Point

2.56 g of sul...

Question

$2.56 g$ of sulphur in $100 g$ of $C S_{2}$ has depression in freezing point of ${0.010}^{\circ} C$ . Atomicity of sulphur is $C S_{2}$ is:(Given, $K_{f} = {0.1}^{\circ} m o l a l^{- 1})$

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Solution

The correct option is B $8$
Let atomicity of sulphur is $n$ , then it exists as $S_{n}$ .
$∴$ Molar mass, $m = 32 n$
Now from, $△ T_{f} = \frac{1000 w K_{f}}{m w}$
$0.010 = \frac{1000 \times 2.56 \times 0.1}{m \times 100}$
or $m = \frac{1000 \times 2.56 \times 0.1}{0.010 \times 100} = 256$
or $32 n = 256$
or, $n = \frac{256}{32} = 8$

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2.56 g of sulphur in 100 g of CS2 has depression in freezing point of 0.010∘C. Atomicity of sulphur is CS2 is:(Given, Kf=0.1∘molal−1)

The correct option is B 8Let atomicity of sulphur is n, then it exists as Sn.∴ Molar mass, m=32nNow from, △Tf=1000 w Kfm w0.010=1000×2.56×0.1m×100or m=1000×2.56×0.10.010×100=256or 32n=256or, n=25632=8

$2.56 g$ of sulphur in $100 g$ of $C S_{2}$ has depression in freezing point of ${0.010}^{\circ} C$ . Atomicity of sulphur is $C S_{2}$ is:(Given, $K_{f} = {0.1}^{\circ} m o l a l^{- 1})$