The correct option is B 32(2^7)^2 × nbsp;(2^ 3)^3 =2^14 × 2^ 9 nbsp; nbsp; nbsp; nbsp; nbsp; nbsp;[∵ (a^m)^n = a^mn] =2^14 9 nbsp; ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Power of a Power

272×2-33=

Question

$(2^{7})^{2} \times (2^{- 3})^{3}$ = ______

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 32
$(2^{7})^{2} \times (2^{- 3})^{3}$

$= 2^{14} \times 2^{- 9}$ $[∵ (a^{m})^{n} = a^{m n}]$

$= 2^{14 - 9}$ $[∵ a^{m} \times a^{n} = a^{m + n}]$

$= 2^{5}$

$= 32$

Suggest Corrections

Similar questions

Simplify $\frac{27^{\frac{2}{3}}}{9^{\frac{1}{2}} \cdot 3^{\frac{3}{2}}}$

(9^{4 / 3} \div 27^{2 / 3}) \times 3^{3 / 2}

\frac{27^{\frac{2}{3}}}{9^{\frac{1}{2}} \times 3^{\frac{3}{2}}}

Simplify and write in exponential form: $3^{3}$ x $3^{- 2}$ x $27^{2}$

(9^{4 / 3} \div 27^{2 / 3}) \times 3^{3 / 2}

Join BYJU'S Learning Program