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Standard X

Physics

Latent Heat

2 kg of ice m...

Question

2 kg of ice melts when water at $100^{\circ}$ is poured in a hole drilled in a block of ice. What mass of water was used?

Given: Specific heat capacity of water=4200 J k $g^{- 1} K^{- 1}$ ,specific latent heat of ice= $336 \times 10^{3} J k g^{- 1}$ .

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Solution

Since the whole block does not melt and only 2 kg of it melts, so the final temperature would be 0^oC. Let mass of water used be 'm' kg.

Heat lost by hot water = Heat gained by ice

$\Rightarrow m \times 4200 \times (100 - 0) = 2 \times 336 \times 10^{3}$

$\Rightarrow m = 1.6 k g$

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Similar questions

10 kg

of ice completely melts when water at

100^{\circ} C

is poured into a hole drilled in the ice. If the specific heat capacity of water is

4200 {J kg}^{- 1}^{\circ} C^{- 1}

and the specific latent heat of melting of ice is

336 \times 10^{3} {J kg}^{- 1}

, the amount of the water needed is

Q. A piece of ice of mass

40 g

is added to

200 g

of water at

50^{o} C

. Calculate the final temperature of water when all the ice has melted. Specific heat capacity of water

= 4200 J k g^{- 1} K^{- 1}

and specific latent heat of fusion of ice

= 336 \times 10^{3} J k g^{- 1}

40 g

of ice at

0^{o} C

is used to bring down the temperature of certain mass of water at

60^{o} C t o 10^{o} C

. Find the mass of water used.
[Specific heat capacity of water

= 4200 J K g^{- 1} C^{- 1}

[Specific latent heat of fusion of ice

= 336 \times 10^{3} J k g^{- 1}

]

250 g

of water at

30^{o} C

is contained in a copper vessel of mass

50 g

. Calculate the mass of ice required to bring down the temperature of the vessel and its contents to

5^{o} C

. Given : specific latent heat of fusion of ice

= 336 \times 10^{3} J k g^{- 1}

, specific heat capacity of copper

= 400 J k g^{- 1} K^{- 1}

, specific heat capacity of water

= 4200 J k g^{- 1} K^{- 1}

The amount of heat energy required to convert 1 kg of ice at $- 10^{\circ} C$ to water at $100^{\circ} C$ is 7,77,000 J. Calculate the specific latent heat of ice.

Specific heat capacity of ice = 2100 J $k g^{- 1} K^{- 1}$ , specific heat capacity of water=4200 J k $g^{- 1} K^{- 1}$ .

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2 kg of ice melts when water at 100∘ is poured in a hole drilled in a block of ice. What mass of water was used? Given: Specific heat capacity of water=4200 J kg−1 K−1,specific latent heat of ice=336×103 J kg−1.

Since the whole block does not melt and only 2 kg of it melts, so the final temperature would be 0 oC. Let mass of water used be 'm' kg. Heat lost by hot water = Heat gained by ice ⇒m×4200×(100−0)=2×336×103 ⇒m=1.6 kg

2 kg of ice melts when water at $100^{\circ}$ is poured in a hole drilled in a block of ice. What mass of water was used?

Given: Specific heat capacity of water=4200 J k $g^{- 1} K^{- 1}$ ,specific latent heat of ice= $336 \times 10^{3} J k g^{- 1}$ .

Since the whole block does not melt and only 2 kg of it melts, so the final temperature would be 0^oC. Let mass of water used be 'm' kg.

Heat lost by hot water = Heat gained by ice

$\Rightarrow m \times 4200 \times (100 - 0) = 2 \times 336 \times 10^{3}$

$\Rightarrow m = 1.6 k g$