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Standard XII

Chemistry

Ideal Gas Equation

2 L of SO2 ...

Question

$2 L$ of $S O_{2}$ gas at $760$ $m m H g$ is transferred to $10$ L flask containing oxygen at a participate temperature, the particular pressure of $S O_{2}$ in the flask is:

63.3 m m H g

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152 m m H g

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760 m m H g

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1330 m m H g

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Solution

The correct option is A $152 m m H g$
Let us consider the problem :-
Putting $2$ litre of any gas into a $10$ litre flask. and temprature is constant.
Since pressure drop by a factor of $\frac{10}{2} = 5$
Hence the partial pressure of $S O_{2}$
$\frac{760 m m H g}{5}$
$= 152$ mm Hg.

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1L flask contains nitrogen along with a drop or two of water at $40^{\circ} C$ , the total pressure being 760 torr. If all the conents are transferred to another flask of 0.5 L at the same temperature, the pressure set up in the second flask will be (aqueous tension at $40^{\circ} C = 55 t o r r)$

S O_{2}

at STP contained in a flask was replaced by

O_{2}

under identical conditions of pressure, temperature and volume. Then the weight of

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1 L flask contains nitrogen along with a drop or two of water at $40^{\circ} C$ , the total pressure is 760 torr. If all the contents are transferred to another flask of 0.5 L at the same temperature, the pressure set up in the second flask will be (aqueous tension at $40^{\circ} C = 55 t o r r)$

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2 L of SO2 gas at 760 mm Hg is transferred to 10 L flask containing oxygen at a participate temperature, the particular pressure of SO2 in the flask is:

The correct option is A 152 mm HgLet us consider the problem :-Putting 2 litre of any gas into a 10 litre flask. and temprature is constant.Since pressure drop by a factor of 102=5Hence the partial pressure of SO2760mmHg5=152 mm Hg.

$2 L$ of $S O_{2}$ gas at $760$ $m m H g$ is transferred to $10$ L flask containing oxygen at a participate temperature, the particular pressure of $S O_{2}$ in the flask is:

The correct option is A $152 m m H g$
Let us consider the problem :-
Putting $2$ litre of any gas into a $10$ litre flask. and temprature is constant.
Since pressure drop by a factor of $\frac{10}{2} = 5$
Hence the partial pressure of $S O_{2}$
$\frac{760 m m H g}{5}$
$= 152$ mm Hg.