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Mole Concept

SO2 at STP co...

Question

$S O_{2}$ at STP contained in a flask was replaced by $O_{2}$ under identical conditions of pressure, temperature and volume. Then the weight of $O_{2}$ will be ______ of $S O_{2}$ .

A

half

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B

one fourth

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C

twice

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D

four times

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Solution

The correct option is A half
$S O_{2}$ at STP contained in a flask was replaced by $O_{2}$ under identical conditions of pressure, temperature and volume. Then the weight of $O_{2}$ will be half of $S O_{2}$ . Since, the temperature, pressure and volume are identical, the number of moles are identical.
$n_{O_{2}} = n_{S O_{2}}$
$\frac{W_{O_{2}}}{M_{O_{2}}} = \frac{W_{S O_{2}}}{M_{S O_{2}}}$
$\frac{W_{O_{2}}}{16} = \frac{W_{S O_{2}}}{32}$
$W_{O_{2}} = \frac{W_{S O_{2}}}{32} \times 16 = \frac{W_{S O_{2}}}{2}$

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