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Question

2(bc cos A+ca cos B+ab cos C)=a2+b2+c2

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Solution

2(bc cos A+ca cos B+ab cos C)=a2+b2+c2LHS=2bc cos A+2ca cos B+2ab cos C=2bc b2+c2a22bc+2ca a2+c2b22ca+2ab a2+b2c22ab=b2+c2a2+a2+c2b2+a2+b2c2=a2+b2+c2=RHS


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