2(bc cos A+ca cos B+ab cos C)=a2+b2+c2
2(bc cos A+ca cos B+ab cos C)=a2+b2+c2LHS=2bc cos A+2ca cos B+2ab cos C=2bc b2+c2−a22bc+2ca a2+c2−b22ca+2ab a2+b2−c22ab=b2+c2−a2+a2+c2−b2+a2+b2−c2=a2+b2+c2=RHS
2(bc cos A+ ca cos B + ab cos C)=
In △ ABC, if 2(bc cos A + ca cos B + ab cos C) =