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Question

2 plastic balls have masses of 100 g and 200 g. The 100 g ball is moving at 3 ms1 and hits the 200 g stationary ball. They collide with each other and after the collision, the 100 g ball moves with a velocity of 1.5 ms1 in the same direction. Calculate the velocity of the other ball after collision.


A
0.75 ms1
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B
0.75 kms1
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C
0.75 cms1
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D
0.57 ms1
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Solution

The correct option is A 0.75 ms1
Let m1=100 g=0.1 kg be the mass of first ball, m2=200 g=0.2 kg be the mass of second ball.
u1 initial velocity of first ball before collision =3 ms1
u2 initial velocity of second ball before collision =0 ms1
v1 final velocity of first ball after collision =1.5 ms1
v2 final velocity of second ball after collision
Applying law of conservation of momentum we can write,
m1u1+m2u2=m1v1+m2v2
Substituting values
0.1×3+0.2×0=0.1×1.5+0.2×v2
0.3=0.15+0.2×v2
Or v2=0.75 ms1

Physics

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