wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two small glass spheres of masses 10 g and 20 g are moving in a straight line in the same direction with velocities of 3ms−1 and 2ms−1 respectively. They collide with each other. After collision, glass sphere of mass 10 g moves with a velocity of 2.5ms−1. Find the velocity of the second ball after collision.

A
2.25ms1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
5.5ms1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2.75ms1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
7.5ms1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 2.25ms1
Here, m1=10g=101000=0.01kg

m2=20g=0.02kg

u1=3ms1;u2=2ms1

v1=2.5ms1;v2=?

Total momentum of both the spheres before collision =m1u1+m2u2

=0.01×3+0.02×2=0.07kgms1

Total momentum of both the spheres after collision

=m1v1+m2v2

=0.01×2.5+0.02v2=0.025+0.02v2

Now, according to the law of conservation of momentum,

Total momentum after collision =Total momentum before collision

0.025+0.02v2=0.07

or 0.02v2=0.070.025=0.045

or v2=0.0450.02=2.25ms1

flag
Suggest Corrections
thumbs-up
2
similar_icon
Similar questions
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Law of Conservation of Momentum
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon