You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Non Contact Collision

Two spheres o...

Question

Two spheres of masses, $20 g$ and $40 g$ are moving on a straight frictionless path in the same direction with velocities of $3 m/s$ and $2 m/s$ respectively. They collide with each other and after collision, the sphere of mass $20 g$ moves with a velocity of $2.5 m/s$ in the same direction as before collision. Find the velocity of the second ball after collision.

4.25 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3.25 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5.25 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.25 m/s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $2.25 m/s$
From law of conservation of linear momentum,

$m_{1} u_{1} + m_{2} u_{2} = m_{1} v_{1} + m_{2} v_{2}$

$\Rightarrow 0.02 \times 3 + 0.04 \times 2 = 0.02 \times 2.5 + 0.04 \times v_{2}$

$\Rightarrow v_{2} = 2.25 m/s$

Hence, option $(D)$ is the correct answer.

Suggest Corrections

Similar questions

Q. Two small glass spheres of masses 10 g and 20 g are moving in a straight line in the same direction with velocities of

3 m s^{- 1}

and

2 m s^{- 1}

respectively. They collide with each other. After collision, glass sphere of mass 10 g moves with a velocity of

2.5 m s^{- 1}

. Find the velocity of the second ball after collision.

Two plastic spheres of masses 10 g and 20 g are moving in a straight line in the same direction with velocities of 3 ms^–1 and 2 ms^–1 respectively. They collide with each other and after collision the plastic sphere of mass 10 g moves with a velocity of 2.5 ms^–1. Find the velocity of the second ball after collision.

Q. Two objects of masses 100 g and 200 g are moving along the same line and same direction with velocities of

2 m s^{- 1} a n d 1 m s^{- 1},

respectively. They collide and after the collision, the first object moves at a velocity of

1.67 m s^{- 1}

. Determine the velocity of the second object.

Q. Two masses,

m_{1}

and

m_{2}

were moving in opposite direction with speeds of

20 m/s

and

10 m/s

respectively. They collide and

m_{1}

moves with

15 m/s

after collision in its same direction as of before collision. What is the speed and direction of the second particle after collision, if the coefficient of restitution is

2 / 3 ?

Two objects of masses 100 g and 200 g are moving along the same line and direction with velocities of 2 ms⁻¹ and 1 ms⁻¹, respectively. They collide and after the collision, the first object moves at a velocity of 1.67 ms⁻¹. Determine the velocity of the second object.

Join BYJU'S Learning Program

The correct option is D 2.25 m/sFrom law of conservation of linear momentum, m1u1+m2u2=m1v1+m2v2 ⇒0.02×3+0.04×2=0.02×2.5+0.04×v2 ⇒v2=2.25 m/s Hence, option (D) is the correct answer.

The correct option is D $2.25 m/s$
From law of conservation of linear momentum,

$m_{1} u_{1} + m_{2} u_{2} = m_{1} v_{1} + m_{2} v_{2}$

$\Rightarrow 0.02 \times 3 + 0.04 \times 2 = 0.02 \times 2.5 + 0.04 \times v_{2}$

$\Rightarrow v_{2} = 2.25 m/s$

Hence, option $(D)$ is the correct answer.