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Introduction to Optical Isomerism

2. The quantu...

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2. The quantum number for the outermost electron of an element are n=2, l=0,m=0,s=+1/2. The atom is ?

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The quantum numbers for an electron in the outermost orbital of an element are given as $n = 2, l = 0, m = 0, s = - \frac{1}{2}$ . The atom could be:

The quantum numbers for the outermost electron of an element are given below as $n = 2, l = 0, m = 0, s = + \frac{1}{2}$ . The atoms is

Q. Given set of quantum numbers for a multi-electron atom is:

$n$	$l$	$m$	$s$
$2$	$0$	$0$	$+ 1 / 2$
$2$	$0$	$0$	$- 1 / 2$

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n

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Q. The values of four quantum numbers of valence electrons in an element X are n = 4, l = 0, m = 0,

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. The element is:

Q. The values of four quantum numbers of valence electron of an element

X

n = 4, l = 0, m = 0, s = 1 / 2

. The element is:

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