CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

20 kg + 500 g + 200 mg + 11.5 kg = ___ g

A
32000.2 g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
28000 g
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
C
30000 g
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
D
31000.4 g
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
Open in App
Solution

The correct option is A 32000.2 g
1 kg=1000 g 20 kg=20×1000 g=20000 g11.5 kg=11.5×1000 g=11500 g

Now, 1 g=1000 mg. 1 mg=11000 g200 mg=200×11000 g=0.2 g grams20000.000500.0000.200+11500.000–––––––––––––32000.200 =32000.2 g

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
For Good Measure
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon