$20$ liters of a mixture contains milk and water in the ratio $5 : 3$ . If $4$ liters of this mixture is replaced by $4$ liter of milk, the ratio of milk in the new mixture would be

2 : 1

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7 : 3

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8 : 3

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4 : 3

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Solution

The correct option is B $7 : 3$
Let the amount of milk and water in $20$ liter mixture is $5 x$ and $3 x$
If $4$ liter of mixture is replaced by $4$ liter of milk
milk $= 5 x + 4$
water $= 3 x$
Then,
$5 x + 4 + 3 x = 20$
$x = 2$
Ratio of milk and water $= \frac{5 x + 4}{3 x}$
$= \frac{7}{3}$
$= 7 : 3$

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20 liters of a mixture contains milk and water in the ratio 5:3. If 4 liters of this mixture is replaced by 4 liter of milk, the ratio of milk in the new mixture would be

The correct option is B 7:3Let the amount of milk and water in 20 liter mixture is 5x and 3xIf 4 liter of mixture is replaced by 4 liter of milk milk =5x+4water =3x Then,5x+4+3x=20x=2Ratio of milk and water =5x+43x=73=7:3

$20$ liters of a mixture contains milk and water in the ratio $5 : 3$ . If $4$ liters of this mixture is replaced by $4$ liter of milk, the ratio of milk in the new mixture would be