The correct option is C V=123.7 L
This is an adiabatic irreversible process, so for this process
PVγ= Constant, is not applicable
W=−Pext(V2−V1)
V2 is final volume,V1 is initial volume,W is work done
T2 is final temperature, T1 is initial temperature
But for adiabatic process,
W=dU=(P2V2−P1V1γ−1)
Also, we know;
PV=nRT⇒10×20=n×0.082×273⇒n=8.92. moles
Also, Comparing the work done, We get
−Pext(V2−V1)=(P2V2−P1V1γ−1)
⇒−1×(V2−10)=1×V2−10×201.67−1
⇒(10−V2)=V2−2000.67
⇒6.7−0.67 V2=V2−200
⇒206.7=1.67 V2
⇒V2=123.75 L