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Grignard Reagents

20 mL of 0.1 ...

Question

20 mL of 0.1 M Bacl2 is mixed with 30 mL of 0.2 M Al2(SO4)3. What is the weight of BaSO4 formed?( A of Ba=137).

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Q. Calculate the amount of precipitate of

B a S O_{4}

formed when 30 mL of 0.1 M

B a C l_{2}

is mixed with 40 mL of 0.2 M

A l_{2} (S O_{4})_{3}

.
(Molar mass of barium = 137 g/mol, Molar mass of Al = 27 g/mol).

Q. The amount of

B a S O_{4}

formed upon mixing

100

20.8 %

B a C l_{2}

50

9.8 %

H_{2} S O_{4}

solution will be:

(Given that molecular weight of

B a = 137, C l = 35.5, S = 32, H = 1

O = 16

Q. The amount of

B a S O_{4}

formed upon mixing

100

20.8 %

B a C l_{2}

50

9.8 %

H_{2} S O_{4}

solution will be:
[Ba

= 137

= 35.5

= 32

= 1

= 16

Q. 100 mL of 20.8%

B a C l_{2}

solution and 50 mL of 9.8%

H_{2} S O_{4}

solution will form

B a S O_{4}

(B a = 137, C l = 35.5, S = 32, H = 1, O = 16)

B a C l_{2} + H_{2} S O_{4} \to B a S O_{4} + 2 H C l

20

1 M B a C l_{2}

25

0.1

N a_{2} S O_{4}

are mixed to form

B a S O_{4}

. The amount of

B a S O_{4}

precipitated are:

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