Question

20% of dolls produced in a factory were defective, 25% of the remaining were damaged . If 4800 dolls were left over, what was the original number of dolls?

Answer 1

Let original No. of doll $=x$

No. of defected dolls $=\frac{20x}{100}$

Remaining dolls $=\frac{80x}{100}$

Number of damaged dolls $=25\%$ of $\frac{80x}{100}$

$=\frac{20x}{100}$

No. of dolls leftover $=4800$

$x-\left(\frac{40x}{100}\right)=4800$

$\frac{60x}{100}=4800$

$x=8000$

Original No. of dolls $=8000$