$200$ g of ice at $0^{o}$ C converts into water at $0^{o}$ C in $1$ minute when heat is supplied to it at a constant rate. In how much time $200$ g of water at $0^{o}$ C will change to $20^{o}$ C? Take specific latent of ice $= 336 J g^{- 1}$

5 s

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10 s

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15 s

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20 s

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Solution

The correct option is C 15 s
Heat supplied to melt ice =mL= $200 \times 336 = 67200 J$
For t=60 sec
Heat supply rate Q = $\frac{67200}{60} = 1120 J / s$
Heat required to heat water by 20 $^{o} C$
Heat required = $200 \times 4.2 \times 20 = 16800$
Time required = $\frac{16800}{1120} = 15 s$

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200 g of ice at 0 $^{\circ} C$ converts into the water at 0 $^{\circ} C$ in 1 minute when heat is supplied to it at a constant rate. In how much time 200 g of water at 0 $^{\circ} C$ will change to 20 $^{\circ} C$ ? Specific latent heat of ice = 336 Jg $^{- 1}$ .

200 g of ice at $0^{\circ} C$ convert into water at $0^{\circ} C$ in 1 minute when heat is supplied to it at a constant rate.In how much time 200 g of water at $0^{\circ} C$ will change to $20^{\circ} C$ ?Take specific latent heat of ice =336 ) J $g^{- 1}$ .