$200 g m s$ as a fraction of $1 k g$ is:

\frac{1}{2}

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\frac{1}{3}

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\frac{1}{4}

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\frac{1}{5}

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Solution

The correct option is C $\frac{1}{5}$
$1 k g = 1000 g$

Let the fraction be $x$

$x = \frac{200 g}{1000 g}$

$x = \frac{1}{5}$

So, the fraction is $\frac{1}{5}$ .

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\frac{\sqrt[3]{a^{5} b^{1 / 2}} \sqrt[4]{a^{- 1}}}{(a^{2} \sqrt[5]{a b^{3}})^{2}}

What is 800g of 1 kg as a fraction in its simplest form.

(x^{1 / 3} + y^{1 / 3}) (x^{2 / 3} - x^{1 / 3} y^{1 / 3} + y^{2 / 3})

x = 4 \frac{5}{7}

y = 5 \frac{2}{7}

Multiply and express as a mixed fraction:

(a) (b)

(e) (f)

1 \frac{2}{5} + 3 \frac{1}{5} + 4 \frac{3}{5} = ?

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