200 J of work was done against gravity to lift an object of mass 1 kg to a particular height. If the body is dropped from that height, what will be its velocity when it reaches the bottom?

50J

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100J

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200J

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400J

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Solution

The correct option is B
100J

Potential energy attained by the body = 200 J
When it is dropped and reaches the bottom, all its potential energy will be converted to kinetic energy.
If v is the velocity at the bottom, then,

$\frac{1}{2} m v^{2} = 200 J v^{2} = 400$
$v = 20 m / s$

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200 J of work was done against gravity to lift an object of mass 1 kg to a particular height. If the body is dropped from that height, what will be its velocity when it reaches the bottom?

The correct option is B 100J Potential energy attained by the body = 200 J When it is dropped and reaches the bottom, all its potential energy will be converted to kinetic energy. If v is the velocity at the bottom, then, 12mv2=200Jv2=400 v=20 m/s

The correct option is B
100J

Potential energy attained by the body = 200 J
When it is dropped and reaches the bottom, all its potential energy will be converted to kinetic energy.
If v is the velocity at the bottom, then,

$\frac{1}{2} m v^{2} = 200 J v^{2} = 400$
$v = 20 m / s$