A man lifts a mass of 20 kg to a height of 2.5 m. Assuming that the force of gravity on 1 kg mass is 10 N, Find the work done by the man. $(t a k e g = 10 m s^{- 2})$

50 J

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100 J

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250 J

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500 J

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Solution

The correct option is D
500 J

Given, mass, $m = 20 k g$
Displacement, $s = 2.5 m$
Acceletation due to gravity, $g = 10 m s^{- 2}$
Force = mg = $20 k g \times 10 m s^{- 2}$ $= 200 N$
Work done = $F \times s$
W = $200 N \times 2.5 m = 500 J$

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A man lifts a mass of 20 kg to a height of 2.5 m. Assuming that the force of gravity on 1 kg mass is 10 N, Find the work done by the man.(take g = 10 ms−2)

The correct option is D 500 J Given, mass, m=20 kg Displacement, s=2.5 m Acceletation due to gravity, g=10 ms−2 Force = mg = 20 kg×10 ms−2 =200 N Work done = F×s W = 200 N × 2.5 m=500 J

A man lifts a mass of 20 kg to a height of 2.5 m. Assuming that the force of gravity on 1 kg mass is 10 N, Find the work done by the man. $(t a k e g = 10 m s^{- 2})$

The correct option is D
500 J

Given, mass, $m = 20 k g$
Displacement, $s = 2.5 m$
Acceletation due to gravity, $g = 10 m s^{- 2}$
Force = mg = $20 k g \times 10 m s^{- 2}$ $= 200 N$
Work done = $F \times s$
W = $200 N \times 2.5 m = 500 J$