Question

200 MeV energy is released when one nucleus of ${}^{235}U$ undergoes fission. The number of fissions per second required for producing a power of 1Megawatt is :

• A. 3.125 x 10${}^{12}$
• B. 3.125 x 10${}^{16}$
• C. 3.125 x 10${}^8$
• D. 3.125 x 10${}^{10}$

Answer 1

The correct option is B 3.125 x 10${}^{16}$

1 MeV $=1.6\times {10}^{-13}J$
200 MeV $\to$ one nucleus
No. of fission required $=\frac{{10}^{6}J/s}{200\times 1.6\times {10}^{-13}}$

$=\frac{{10}^{17}}{3.2}$

$=3.125\times {10}^{16}$