Question

The energy released by the fission of one uranium atom is 200 MeV. The number of fissions per second required to produce 3.2 W of power is

• A. ${10}^7$
• B. ${10}^{10}$
• C. ${10}^{15}$
• D. ${10}^{17}$

Answer 1

The correct option is D

${10}^{17}$

Energy released = 200 MeV = 200 $\times {10}^6$eV = 200 $\times {10}^6\times 1.6\times {10}^{-19}J$. Therefore, the required number is
$\frac{3.2}{200\times {10}^6\times 1.6\times {10}^{-19}}={10}^{17}$