Question

The energy released in the fission of a single uranium nucleus is $200MeV$.Then number of fission per second to produce $5$milliwatt power is

• A. 1.56 x10${}^8$
• B. 1.56 x10${}^{13}$
• C. 3.12x 10${}^{18}$
• D. 3.12x 10${}^{13}$

Answer 1

Answer: (A)

1.56 x10${}^8$

No of fission reaction needed $=\frac{5\times {10}^{-3}}{{10}^6\times 200\times 1.6\times {10}^{-19}}$ fissions per second

$=1.5625\times {10}^8$ fission per second.