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Byju's Answer
Standard XII
Physics
Bulk Modulus
200 ml of C...
Question
200
m
l
of
C
2
H
4
is burnt in just sufficient air (containing
20
%
oxygen). Calculate the resultant mixture composition at
100
∘
C
.
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Solution
Since air contains mainly
N
2
and
O
2
.
%
O
2
=
20
%
%
N
2
=
100
−
20
=
80
%
Now,
C
2
H
4
+
3
O
2
→
2
C
O
2
+
2
H
2
O
V
3
V
2
V
2
V
Used
:
200
m
l
600
m
l
400
m
l
400
m
l
Left
:
0
m
l
0
m
l
∴
Now,
Total volume of air
=
x
m
l
Again,
O
2
→
20
%
of
x
=
600
m
l
x
=
600
×
100
20
m
l
=
3000
m
l
∴
Volume of
N
2
in mixture
=
80
%
of
3000
m
l
=
2400
m
l
∴
(
i
)
V
N
2
=
2400
m
l
(
i
i
)
V
C
O
2
=
400
m
l
(
i
i
i
)
V
H
2
O
=
400
m
l
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