2000 cal of heat is supplied to 200 g of water. Find the rise in temperature. (Specific heat of water = 1 cal /g °c)
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Solution
given , m=200g,Q=2000cal,Δθ=?, , specific heat of water c=1cal/g °cNow , heat required to raise the temperature of water is given by the definition of specific heat ,
Q=m c Δθ
or Δθ=Q/(m c)
=2000/(200×1)
=10°C