2000 J of heat is required to melt 40 Kg of substance, then the specific latent heat of substance is

80000 J/kg

No worries! We‘ve got your back. Try BYJU‘S free classes today!

800 J/kg

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.02 J/kg

No worries! We‘ve got your back. Try BYJU‘S free classes today!

50 J/kg

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
50 J/kg

L = Q/m = 2000 J/40 Kg = 50 J/kg

Suggest Corrections

Similar questions

The latent heat of fusion of ice is:

(a) 33.4 $\times 10^{5} J / K g$ (b) 22.5 $\times 10^{5} J / K g$
(c) 33.4 $\times 10^{4} J / K g$ (d) 2.25 $\times 10^{4} J / K g$

Q. The latent heat of vaporisation of water is :
(a) 2.25 × 10⁶ J/kg
(b) 3.34 × 10⁶ J/kg
(c) 22.5 × 10⁴ J/kg
(d) 33.4 × 10⁵ J/kg

A lead ball at $30^{\circ} C$ is dropped from a height of $6.2 k m$ . The ball is heated due to the air resistance and it completely melts just before reaching the ground. The molten substance falls slowly on the ground. Calculate the latent heat of fusion of lead. Specific heat capacity of lead = $126 J k g^{- 1}^{\circ} C^{- 1}$ and melting point of lead = $330^{\circ} C$ . Assume that any mechanical energy lost is used to heat the ball. Use $g$ = $10 m s^{- 2}$ .