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Stoichiometric Calculations

21.2 g sample...

Question

$21.2 g$ sample of impure $N a_{2} C O_{3}$ is dissolved and reacted with a solution of $C a C l_{2}$ , the weight of precipitate of $C a C O_{3}$ is $10.0 g$ . Which of the following statements is/are correct ?

The

%

purity of

N a_{2} C O_{3}

50 %

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The percentage purity of

N a_{2} C O_{3}

60 %

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The number of moles of

N a_{2} C O_{3} =

that of

C a C O_{3} = 0.1 mol

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The number of moles of

N a C l

formed is

0.1 mol

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Solution

The correct option is C The number of moles of $N a_{2} C O_{3} =$ that of $C a C O_{3} = 0.1 mol$
Molar mass of $C a C O_{3} = 100 {g mol}^{- 1}$
Molar mass of $N a_{2} C O_{3} = 106 {g mol}^{- 1}$

$N a_{2} C O_{3} + C a C l_{2} \to C a C O_{3} + 2 N a C l$
(a) From stoichiometry,
moles of $C a C O_{3} = \frac{10}{100} = 0.1 mol$
moles of $N a_{2} C O_{3} =$ moles of $C a C O_{3} = \frac{1}{2} \times$ moles of $N a C l$
mass of $N a_{2} C O_{3} = 0.1 \times 106 = 10.6 g$
$%$ purity $N a_{2} C O_{3} = \frac{10.6}{21.2} = 100 = 50 %$

c) moles of $C a C O_{3} = \frac{10}{100} = 0.1 mol$
(d) Moles of $N a C l = 2 \times 0.1 = 0.2 mol$

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21.2 g

sample of impure

N a_{2} C O_{3}

is dissolved and reacted with a solution of

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, the weight of

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21.2 g

sample of impure

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21.2 g sample of impure Na2CO3 is dissolved and reacted with a solution of CaCl2, the weight of precipitate of CaCO3 is 10.0 g. Which of the following statements is/are correct ?

$21.2 g$ sample of impure $N a_{2} C O_{3}$ is dissolved and reacted with a solution of $C a C l_{2}$ , the weight of precipitate of $C a C O_{3}$ is $10.0 g$ . Which of the following statements is/are correct ?