21.5 g of sodium chloride dissolveds in 60 g of water at 25°C. Calculate the solubility of sodium chloride in water at that temperature.

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Solution

According to the question:
60 gm of water dissolves 21.5 gm of NaCl.
So, 100 gm of water will dissolve $= \frac{21.5}{60} \times 100 = 35.8 g of NaCl$
Thus, the solubility of NaCl = 35.8 gm

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21.5 g of sodium chloride dissolveds in 60 g of water at 25°C. Calculate the solubility of sodium chloride in water at that temperature.

According to the question: 60 gm of water dissolves 21.5 gm of NaCl. So, 100 gm of water will dissolve =21.560×100=35.8 g of NaCl Thus, the solubility of NaCl = 35.8 gm

According to the question:
60 gm of water dissolves 21.5 gm of NaCl.
So, 100 gm of water will dissolve $= \frac{21.5}{60} \times 100 = 35.8 g of NaCl$
Thus, the solubility of NaCl = 35.8 gm