9.72 g of potassium chloride dissolves in 30 g of water at 70°C. Calculate the solubility of potassium chloride at that temperature.

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Solution

According to the question:
30 gm of water dissolves 9.72 gm of KCl.
So, amount of KCl that gets dissolved in 100 gm of water $= \frac{9.72}{30} \times 100 = 32.4$
Thus, the solubility of KCl = 32.4 gm

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Q. Maximum of 9.72 g of potassium chloride dissolves in 30 g of water at

70^{\circ}

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Q. Pragya tested the solubility of three different substances at different temperatures and collected the data as given below( results are given in the following table, as grams of substance dissolved in 100 grams of water to form a saturated solution).

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Ammonium chloride	24	37	41	55	66

(a) What mass of potassium nitrate would be needed to produce a saturated solution of potassium nitrate in 50 grams of water at 313 K?

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9.72 g of potassium chloride dissolves in 30 g of water at 70°C. Calculate the solubility of potassium chloride at that temperature.

According to the question: 30 gm of water dissolves 9.72 gm of KCl. So, amount of KCl that gets dissolved in 100 gm of water =9.7230×100=32.4 Thus, the solubility of KCl = 32.4 gm

According to the question:
30 gm of water dissolves 9.72 gm of KCl.
So, amount of KCl that gets dissolved in 100 gm of water $= \frac{9.72}{30} \times 100 = 32.4$
Thus, the solubility of KCl = 32.4 gm