Question

21.5 g of sodium chloride dissolves in 60 g of water at 25° C. Calculate the solubility of sodium chloride in water at that temperature.

Answer 1

$$\begin{gathered} \mathrm{Solubility}\mathrm{of}\mathrm{a}\mathrm{solute}=\frac{\mathrm{Weight}\mathrm{of}\mathrm{solute}\mathrm{in}\mathrm{saturted}\mathrm{solution}}{\mathrm{Weight}\mathrm{of}\mathrm{solvent}\mathrm{in}\mathrm{saturated}\mathrm{solution}}\times 100 \\ \mathrm{Solubility}\mathrm{of}\mathrm{a}\mathrm{solute}=\frac{21.5}{60}\times 100 \\ \mathrm{Solubility}\mathrm{of}\mathrm{a}\mathrm{solute}=35.833\mathrm{g}/100\mathrm{mL}\mathrm{of}\mathrm{water} \end{gathered}$$
As water has a density 1 g/cc solubility is expressed as 35.833 g/100 mL of water.