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Question

214.2 g of sugar syrup contains 34.2 g of sugar.

Calculate
(i) molarity of the solution
(ii) mole fraction of sugar in the syrup.


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Solution

Analyzing the given data:

Given Mass of sugar =34.2g

Molar Mass of sugar =342gmol-1

No. of moles of sugar = GivenmassMolecularmass=34.2342=0.1mole

Sugar syrup contains sugar in water.

So, massofwater=(214.2-34.2)g=180g

Molar Mass of Water =18gmol-1
No. of moles of water = GivenmassMolecularmass=18018=10mole

Part (i): Molarity of solution

Molarity(M): The number of moles of a solute dissolved in 1 L (1000 ml) of the solution is known as the molarity of the solution.

Molarity(M)=MoleofsoluteVolumeofsolution(inlitre)

M=0.1180×1000=0.555M

Thus, the molarity of sugar is 0.555 M

Part (ii): Mole fraction of sugar

Total number of moles of solution = mole of solute + mole of solvent =0.1+10=10.1

Molefractionofsugar=MoleofsugarTotalmoleofsolution=0.110.1=0.0099

Thus, mole fraction of sugar in the syrup is 0.0099.


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