2,15, 4, 47, 7, 118, 11, 254,?

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Solution

The correct option is D 16
Given series 2, 15, 4, 47, 7, 118, 11, ?
There are two series
Ist $\Rightarrow 2, 4, 7, 11, ?$
IInd $15, 47, 118, 254$
$∴ 2 + 2 = 4$
$4 + 3 = 7$
$7 + 4 = 11$
$11 + 5 = 16$

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Similar questions

\frac{5}{7} + \frac{9}{11} = \frac{118}{11 a}

a

\frac{1}{3 \times 7} + \frac{1}{7 \times 11} + \frac{1}{11 \times 15} + . . . . . . \frac{1}{47 \times 51}

\begin{matrix} 13 & (27) & 55 11 & (23) & 47 7 & (. . . .) & 31 \end{matrix}

\begin{matrix} 3 & (23) & 7 5 & (47) & 9 6 & (. . . .) & 11 \end{matrix}

4 \frac{7}{11} = \frac{?}{11}

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